On Apr 30, 12:45=A0pm, deepakp <deepak10...@[EMAIL PROTECTED]
> wrote:
> On Apr 30, 9:29 am, Charles Hooper <hooperc2...@[EMAIL PROTECTED]
> wrote:
>
>
>
>
>
> > On Apr 30, 9:49 am, deepakp <deepak10...@[EMAIL PROTECTED]
> wrote:
>
> > > I have an Oracle table that has 2 Date fields..i.e. the data type -
> > > DATE
>
> > > Field 1: =A0START_DATE sample value =A0"2008-04-04 12:00:00";
> > > Field 2: =A0END_DATE =A0sample value =A0"2008-04-07 05:46:07";
>
> > > If I subtract one date from another, I can get the time difference.
>
> > > Round((END_DATE - START_DATE), 4) AS TOTAL_DAYS
>
> > > The above results in 3.7404
>
> > > Between 2008-04-04 and 2008-04-07, there is Saturday and Sunday
which
> > > are 2008-04-05 and 2008-04-06.
> > > I would like them to be excluded.
>
> > > Hence, the resultant that I'm looking for should be 1.7404 =A0-- not
> > > 3.7404
>
> > > Is there a simple way to get the desired solution?
>
> > > Thanks,
> > > Deepak
>
> > Have you tried a Google search of the Usenet archives, or even a
> > regular Google
search?http://groups.google.com/group/comp.databases.orac=
le.misc/browse_thre......
>
> > Charles Hooper
> > IT Manager/Oracle DBA
> > K&M Machine-Fabricating, Inc.
>
> Thank you for your response. I did search online and could not find
> any that showed time difference between. The examples I found were
> similar to the ones you pasted..which show count of days between 2
> dates. That is not what I'm looking for. Instead, I'm looking for time
> difference excluding weekends. =A0The closest match I found in online
> search
washttp://searchoracle.techtarget.com/expert/KnowledgebaseAnswer/0,=
28962...
Assuming that date2 is the later date and that neither date falls on a
Saturday or Sunday, this should do it:
date2 - date1 - 2*(trunc(next_day(date2-1,'FRI')) -
trunc(next_day(date1-1,'FRI')))/7
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